8c^2+26c-7=0

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Solution for 8c^2+26c-7=0 equation:


Simplifying
8c2 + 26c + -7 = 0

Reorder the terms:
-7 + 26c + 8c2 = 0

Solving
-7 + 26c + 8c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-7 + -2c)(1 + -4c) = 0

Subproblem 1

Set the factor '(-7 + -2c)' equal to zero and attempt to solve: Simplifying -7 + -2c = 0 Solving -7 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2c = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2c = 0 + 7 -2c = 0 + 7 Combine like terms: 0 + 7 = 7 -2c = 7 Divide each side by '-2'. c = -3.5 Simplifying c = -3.5

Subproblem 2

Set the factor '(1 + -4c)' equal to zero and attempt to solve: Simplifying 1 + -4c = 0 Solving 1 + -4c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -4c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -4c = 0 + -1 -4c = 0 + -1 Combine like terms: 0 + -1 = -1 -4c = -1 Divide each side by '-4'. c = 0.25 Simplifying c = 0.25

Solution

c = {-3.5, 0.25}

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